Variables zero at the steady state can be discarded from the analysis.
Using
one derives the diagonal term of the Jacobian (with
and
):
Using the steady state equation 9,
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The diagonal terms are negative for
The off-diagonal terms are given by
Thus, a necessary condition for the equilibrium to be stable is
This is possible if and only if
and
.
Condition 12 is stronger than the requirement for the diagonal element to be negative (and is thus also a sufficient condition), and can never be met by variables equal to the lower solution of equations 10 or 11 .
Thus, for any value of the transcription strength
and for any number of coexistant variables
, sufficiently low values of
make the equilibrium stable. If there is a stable equilibrium with
variables on, there is also a stable equilibrium with
variables on, for
. For sufficiently large
, the necessary condition
becomes sufficient for stability (see Figure 5 for an illustration of the validity of this condition).